Anyone familiar with the Hall Effect?

Imagine (on a page) a current flowing through a wire in the 'right' direction -->

Then you set up a magnetic field so that it points into the page X

Then from F = qv X B (X is cross product) means that the positive charge carriers in the wire experience are deflected upwards and sets up a potential difference across the wire. This accumulation results in an electric field and hence a force on the positive charge carriers downward.

Eventually the accumulation reaches equilibrium (when the force is balanced by the magnetic field) and the remaining voltage is called the Hall Voltage.

* Now take away the wire and replace it with an n-type semiconductor. This means that the majority of charge carriers are electrons. These will be deflected downward and hence the direction of the force is upward? By the left-hand rule. Is this right?

* Compare the polarity of the n-type with the p-type assuming all the directions of current and magnetic fields are maintained. I am not sure how to answer this question?? Any hints?

* This is a hard one... Show that the Hall Voltage reverses sign if either the current or magnetic field direction is reversed but the voltage offset reverses sign only if the current direction is reversed.

Whoa? Do I fiddle with V_H = BI / pqt where

1/pq is the Hall Coefficient
B is the magnetic field strength
I is the current
t is time

The problem is that I we have not started electro yet but my lab is early and I have no textbooks on the Hall Effect. Any help is much appreciated. Thanks.

Anyone familiar with the Hall Effect?

Imagine (on a page) a current flowing through a wire in the 'right' direction -->

Then you set up a magnetic field so that it points into the page X

Then from F = qv X B (X is cross product) means that the positive charge carriers in the wire experience are deflected upwards and sets up a potential difference across the wire. This accumulation results in an electric field and hence a force on the positive charge carriers downward.

Eventually the accumulation reaches equilibrium (when the force is balanced by the magnetic field) and the remaining voltage is called the Hall Voltage.

* Now take away the wire and replace it with an n-type semiconductor. This means that the majority of charge carriers are electrons. These will be deflected downward and hence the direction of the force is upward? By the left-hand rule. Is this right?

* Compare the polarity of the n-type with the p-type assuming all the directions of current and magnetic fields are maintained. I am not sure how to answer this question?? Any hints?

* This is a hard one... Show that the Hall Voltage reverses sign if either the current or magnetic field direction is reversed but the voltage offset reverses sign only if the current direction is reversed.

Whoa? Do I fiddle with V_H = BI / pqt where

1/pq is the Hall Coefficient
B is the magnetic field strength
I is the current
t is time

The problem is that I we have not started electro yet but my lab is early and I have no textbooks on the Hall Effect. Any help is much appreciated. Thanks.

Note that if the current is to the right direction and the charges are positive, theur velocity is also to the right. However if the charges are negative, in order to have the current flowing to the right, their velocity must be to the left.
This means that in the force F = qv X B, qv is in the current direction, no matter if the charges are positive or negative, and so, the force will be upward and there will be an accumulation of charges in the top of the wire. If the charges are positive, the electric field will be downward, if the charges are negative, it will be upward.

Ocymoron,

The following link may help.

http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/hall.html