Statisics Question

One in Ten Trillion!!!

I am going to calculate some statistics and see if I can get this right. I'll use two sets. Correct me if I am wrong.

We'll take 20 dice, each having 20 sides and divide them into two groups. We pit these dice against each other, the one's rolling the highest number winning. Statistically it should come out 50% of the time from both groups winning with higher rolls...in other words 50-50 or five from each group coming out on top.

If one group out rolls the other ALL ten times, what are the chances.

1 beating 1 is a 50% chance.
If one die beats 2 dice this is a 25% chance.


If 1 die beats 10 this is 50% to the square root of 10...

50
25
12.5
6.25
3.125
1.5625
0.78125
0.390625
0.1953125
0.09765625 at 1 die beating 10 dice, thus 1 dice has an approximate chance of 1 in a thousand of out rolling 10 other dice.


(2) for this to happen again for another dice we need square the final result of the first.... 0.09765625 Time to find an online calculator....

we get 0.00953674316

(3) to find the chance of another roll beating the 10 in succession we multiply the reminder by the 0.09765625

we get 0.00093132257

repeat to up to 10....

(4) 0.00009094947
(5) 8.88178e-6
(6) 8.6736e-7
(7) 8.47e-8
(8) 8.27e-9
(9) 8.1e-10
(10) 8.1e-11

or basically .000000000081

Thus the chances are 1 in a ten trillion....

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now comes the tough calculations...


1 die beating 50...(the easy part)

and then 10 die beating 50...(the part that takes more time to calculate)
:bugeye:

I'll get back to this soon, unless someone else beats me to the answers!


First I need to get some food in me!

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No response...I'll give it time.

Maybe if I claim boldly that, yes, my calculations are correct it will speed things up. Ahh...why do I bother, I know they are...double check them if you want...

 

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Duplicate. Post in the other thread, please!

Thread closed.

 

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