I had fun riddling this out.

3√2x -1 + 3 = 6

So have fun.

Hint... the variable x is wrapped up in a radical signature.

I had fun riddling this out.

3√2x -1 + 3 = 6

So have fun.

Hint... the variable x is wrapped up in a radical signature.

Reiku, it's hard to tell where the square root symbol ends.

I took the lazy lazy route and assumed the equation is:

3 \sqrt{2x - 1} + 3 = 6
x = 1

:P

P.S. Edited to make it texy.

And if it's 3^Sqrt(2x-1) + 3 = 6, x=1 as well.

I really wish you people would take ten minutes and learn how to use LaTeX.

I'm thinking of implementing this policy.

I have to admit that I'm lazy. I've edited the post.

3*sqrt(2x-1)+3 = 6
3*sqrt(2x-1) = 3
sqrt(2x-1) = 1
2x-1 = 1
2x = 2
x = 1

:shrug:

Edit: Sorry Ben lol

First I'll have to spend 18 hours downloading LaTeX.

First I'll have to spend 18 hours downloading LaTeX.

No you don't. It's implemented on the server side and the equations display as images.

I really wish you people would take ten minutes and learn how to use LaTeX.

I'm thinking of implementing this policy.

Why use force? Just keep encouraging it's use.

Thank you...before this forum I was unaware of what it even was.

LaTex is is well worth having locally, and an 18 hr download is hugely exaggerated; 30-40 minutes I would guess
You need a back-end and an interface as explained here (http://www.artofproblemsolving.com/Wiki/index.php/LaTeX:Downloads), from where you can easily and quickly download (assuming you are using a Windows OS - otherwise look for parallel sites)
If you have Adobe Reader,(or whatever pdf reader your OS supports), all is very straightforward. If you decide to go down this route (and note - it is great for any document, letter etc, not just math), I can link you to user manuals

There's a sticky thread at the top of the Physics forum that explains how to use LaTeX here.

Not to the truth of the equation. Keep trying.

I'm going to throw a hint.

x=14

^3 \sqrt{2x - 1} + 3 = 6
x = 14

^3 \sqrt{2x - 1} + 3 = 6
x = 14

Oh.. ok.. lol

2nd hint...

You must eliminate the radical by equalizing some componants of the original equation.

^3 \sqrt{2x - 1} + 3 = 6
x = 14

I had fun riddling this out.

3√2x -1 + 3 = 6

...

If you aren't going to learn Latex, at least learn how to type this out properly.

(2x-1)^(1/3) + 3 = 6

See? That wasn't so hard.

I thought it was obvious enough.

(2x - 1)^(1/3) + 3 = 6
((2x - 1)^(1/3))^3 = (3)^3
2x - 1 = 27
2x = 28
x = 14

Reinsert into original equation:

(2(14) - 1)^(1/3) + 3 = 6
(28 - 1)^(1/3) + 3 = 6
(27)^(1/3) + 3 = 6
3 + 3 = 6
6 = 6

Is this what you're looking for?

I thought it was obvious enough.
No, it's not. How were we to know you actually mean us to solve ^{^3}\sqrt{2x-1}+3=6 when what you wrote is actually 3\sqrt2 x-1+3=6? Without using LaTeX, you should have written 3√(2x -1) + 3 = 6.

How to interpret 3√2x -1 + 3 = 6? Since the leading three is not superscripted, the only reasonable interpretation is that this is a multiplicative factor, not a modifier of the square root symbol. Since the square root symbol has a higher precedence than multiplication, it applies only to the two to the right of the symbol. Finally, since multiplication has precedence over addition, a mathematician would read your equation as 3\sqrt2 x-1+3=6, which has solution x=4/(3\sqrt 2).

We took some liberty with the original post, assuming you meant instead 3\sqrt{2 x-1}+3=6, which has solution x=1.

If you want to communicate mathematical problems, learn how to write them correctly.

DH... you had it wrong.

Kadark... You solved it!!! Well done!!!

Ok...

I am locking this thread and leaving it as a testament that all people who post here should learn to set their equations in LaTeX.