sevenblu
11-01-06, 04:04 PM
½x² – 5X + 2, whereas x = 2/3
First, I substituted the variables (constants) with 2/3:
½(2/3)² – 5(2/3) + 2
Next, per the order of operations, I solved the exponents:
½(4/9) – 5(2/3) + 2
Then, the multiplication:
2/9 – 10/3 + 2
To make things easier, I found a common denominator:
2/9 – 30/9 + 2
= -28/9 +2
= -3&1/9 + 2
= -1&1/9
My final answer is negative one and one-ninth, however, in the book, the answer to the problem is – (10/9), which is equal to positive one and one ninth.
First, I substituted the variables (constants) with 2/3:
½(2/3)² – 5(2/3) + 2
Next, per the order of operations, I solved the exponents:
½(4/9) – 5(2/3) + 2
Then, the multiplication:
2/9 – 10/3 + 2
To make things easier, I found a common denominator:
2/9 – 30/9 + 2
= -28/9 +2
= -3&1/9 + 2
= -1&1/9
My final answer is negative one and one-ninth, however, in the book, the answer to the problem is – (10/9), which is equal to positive one and one ninth.