View Full Version : Photoelectric question#2


neelakash
12-11-07, 09:41 AM
Why does the photoelectric current I not rise vertically up to its maximum value when the appled potential difference is slightly more positive that the stopping potential?

Simply because,the speed of the photoelectrons also depend on the potential difference they are passing through[apart from the incident ray intensity].As they move their KE becomes converted into PE.As you vary the voltage,the current should vary accordingly...

I do not find any more good reasoning behand this...Can anyone please check?

James R
12-11-07, 06:41 PM
The photoelectric equation gives the maximum energy of the ejected electrons. Ejected electrons can have any energy from zero up to this value.

neelakash
12-11-07, 09:16 PM
That is correct,but that does not simply give you the physics.what happens to the energy of the less energetic electrons?

What is apparent is the concept of conduction band you referred to in the other thread.All electrons in the conduction band do not have the same energy.

About the question: Typically, current is dq/dt.If you have more charge passing through a point in space,you are getting more current.Thus,it is somehow related to the speed of the electrons.

James R
12-11-07, 09:30 PM
The applied stopping potential V will stop any electrons with energies less than eV. Suppose half the electrons are ejected with an energy greater than eV and half are ejected with less energy (even though the incident photon energy is greater than the work function for all the ejected electrons). Then, only half the electrons will form a current.

Increase V and a smaller portion of the electrons (less than half) will now make it across the gap.

draqon
12-11-07, 09:31 PM
differentiate the equation and make it equal to 0 for max value

Reiku
12-12-07, 11:07 PM
The photoelectric equation gives the maximum energy of the ejected electrons. Ejected electrons can have any energy from zero up to this value.

What really happens, is that when we talk about energy moving into metalic plates, releases a small but calculatable zero-point fluctuation. The Photon hits off these plates, and releases two electrons, raised to the power of four.

Reiku
12-12-07, 11:09 PM
differentiate the equation and make it equal to 0 for max value


What are you talking about draq? Seriouly? :bugeye:

James R
12-13-07, 10:01 PM
Reiku:

What really happens, is that when we talk about energy moving into metalic plates, releases a small but calculatable zero-point fluctuation. The Photon hits off these plates, and releases two electrons, raised to the power of four.

If you continue to post this kind of nonsense in science forums, you may be banned from sciforums.