Not Operator in C++

Dear All,
I am running with this simple problem:
I know % is a modulo operator which calculates remainder (int/int).
For example:5%2=1.
Then how does the following work?
if(!(10%2)) cout<<"10 divisible by 2"<<endl;
10%2=0,so, !0 means what?

Thanks
S.Tarafdar

 

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It means just that...not.

When you dont have a subject, not can be implied to mean no true. In C and C++, not true is false, and false is 0. It depends on the computer i believe, but true is anything EXCEPT 0. So when you do !(10%2) you ask saying (10%2) == 0.

-AntonK

 

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Still confused!

Dear AnTonk,
Thank you for your reply.However,I have still confusion.10%2 is a NULL(0),that is why it is false.So,!0 i.e. NOT False is True,isn't it?So,how does it work?

Regards
S.Tarafdar

 

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So... I don't understand what you are asking AntonK!
He already explained you the fact that !(10%2) == !0 == !(false) == true.
0 == false when it's in a condition (if, while, for...)! What do you want to know now? How it is working in the binary or electronic part?! :bugeye:

Have a nice day.

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