Dinosaur
03-08-07, 05:24 PM
Not sure if this is a matter of editorial policy, philosophy, or mathematical logic.
A year or two ago, I wrote a Visual Basic program to analyze geodesics (shortest distance curves) on the surface of a torus.
There are several types of geodesics on the surface of a torus. One type starts at the Outer Equator heads towards the North Polar Circle, reaches a maximum latitude, and returns to the Outer Equator. The numerical data from the program indicates the following.For nearby points on the Equator, the Equator itself is the shortest distance, and there is no geodesic of the type described above between the two points.
For more distance pairs of points on the Equator, a geodesic of the type described above is the shortest distance between the two points and can be significantly shorter than the Equatorial distance. For some pairs of points, there is more than one such geodesic connecting the two points, one of which is shorter than the others.
There is a critical distance along the Equator, intermediate to the above. For this distance, the Equator is the shortest distance between two points, and is equal to the distance between the points along a geodesic of the type described above. Years ago, before writing any pertinent software, I spent a lot of time thinking about geodesics on a torus. My intuition suggested the above type of geodesic, and I spent a lot of time trying to prove the critical distance property.
Perhaps in my college days, I might have come up with some proof, but theory was never my strong point. Since leaving college, I became strictly an applied mathematician and have no hope of proving anything subtle.
The numeric data from my program has convinced me of the validity of the critical distance property, but I wonder if such analysis can be considered a proof.
A year or two ago, I wrote a Visual Basic program to analyze geodesics (shortest distance curves) on the surface of a torus.
There are several types of geodesics on the surface of a torus. One type starts at the Outer Equator heads towards the North Polar Circle, reaches a maximum latitude, and returns to the Outer Equator. The numerical data from the program indicates the following.For nearby points on the Equator, the Equator itself is the shortest distance, and there is no geodesic of the type described above between the two points.
For more distance pairs of points on the Equator, a geodesic of the type described above is the shortest distance between the two points and can be significantly shorter than the Equatorial distance. For some pairs of points, there is more than one such geodesic connecting the two points, one of which is shorter than the others.
There is a critical distance along the Equator, intermediate to the above. For this distance, the Equator is the shortest distance between two points, and is equal to the distance between the points along a geodesic of the type described above. Years ago, before writing any pertinent software, I spent a lot of time thinking about geodesics on a torus. My intuition suggested the above type of geodesic, and I spent a lot of time trying to prove the critical distance property.
Perhaps in my college days, I might have come up with some proof, but theory was never my strong point. Since leaving college, I became strictly an applied mathematician and have no hope of proving anything subtle.
The numeric data from my program has convinced me of the validity of the critical distance property, but I wonder if such analysis can be considered a proof.