Clarification about weak coupling strength

Discussion in 'Physics & Math' started by neelakash, Sep 22, 2009.

  1. neelakash Registered Senior Member

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    491
    When it is said that the relative strength of weak interaction is \(\ 10^{-5}\),what does this mean?

    On calculation I am getting \(\alpha_w=\10^{-3}\) with \(\ G_F=\ 1.16\times\ 10^{-5} \ GeV^{-2}\)

    I had an impression that \(\alpha_w\) should be \(\ 10^{-5}\).Which one is correct?
     
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  3. James R Just this guy, you know? Staff Member

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    Remember, the number is the relative strength. Question is: relative to what?

    For example, to compare the relative strengths the gravitational and electromagnetic forces, you might calculate the strength of the forces between 2 electrons separated by some indicative distance - say the Bohr radius or something. Take the ratio and see what you get.

    Comparing other interactions is sort of similar.
     
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  5. neelakash Registered Senior Member

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    491
    Basically the confusion arose from a problem solved in Y.K.Lim.He states that the interaction strength for different interactions are:

    \(\frac{g^2_h}{\hbar\ c}\) for strong interaction

    \(\frac{e^2}{\hbar\ c}\) for EM interaction

    \(\frac{g^2_w}{\hbar\ c}=\frac{\ G_F\ m^2_p\ c}{\hbar^3}=\ 1.16\ 10^{-5}\ GeV^{-2}\) for weak interaction

    \(\frac{g^2_w}{\hbar\ c}=\frac{\ G\ m^2_p}{\hbar\ c}\) for gravitational interaction

    -where they have used proton as a reference.The point is that if you put the values,you will get the strength of each interaction [like weak int:\(\ 10^{-5}\) or gravitational int. is \(\ 10^{-39}\).They have not calculated any such number for strong interaction.So,I not sure if it is okay to call this as "reletive" or "absolute".
     
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