CompiledMonkey
08-31-02, 11:30 AM
#1.
4(x + 3) = 2(6 + 2x)
4x + 12 = 12 + 4x
0 = 0
Would the answer be 0 or null? Could anyone explain why in either case?
#2.
3(x - 1) + 5 = 3x + 7
3x - 3 + 5 = 3x + 7
3x + 2 = 3x + 7
0 = 5
How can this be? What am I missing here?
4(x + 3) = 2(6 + 2x)
4x + 12 = 12 + 4x
0 = 0
Would the answer be 0 or null? Could anyone explain why in either case?
#2.
3(x - 1) + 5 = 3x + 7
3x - 3 + 5 = 3x + 7
3x + 2 = 3x + 7
0 = 5
How can this be? What am I missing here?